Skip to main content
The normal distribution
Lesson 48 of 75
Standard practice

Normal probabilities

Objective. Calculate intervals and tails accurately.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

Normal probabilities use standardisation and the standard normal cumulative distribution function Φ(z) to find the probability a variable falls below, above, or between given values. P(X < x) = Φ(z), P(X > x) = 1 − Φ(z), and P(a < X < b) = Φ(z_b) − Φ(z_a), where each z is the standardised score. For X ~ N(20, 25), P(X < 25) uses z = (25−20)/5 = 1, so P(X < 25) = Φ(1) ≈ 0.8413. Always subtract from 1 for 'greater than' and subtract two Φ values for an interval.

Worked example

Given X ~ N(30, 16), find the normal probability P(X > 34), using Φ(1) = 0.8413.

using Φ(1) = 0
Illustrated card showing using Φ(1) = 0
  1. 1Standardise: z = (34−30)/4 = 1
  2. 2Find Φ(1) = 0.8413, representing P(X < 34)
  3. 3Apply P(X > 34) = 1 − Φ(1)
  4. 4Compute 1 − 0.8413 = 0.1587

Answer: 0.1587

Concept mastery

Based on your past attempts at this lesson — the question types to practise again come first.

Complete a practice set to see your concept breakdown here.

Practice

Practice happens on its own screen, one question at a time. Answers stay hidden until you submit yours, and you can stop and pick up at the same question later.

Start practising

Common mistake. A frequent error is forgetting to subtract from 1 when finding P(X > x), instead reporting Φ(z) directly as the upper-tail probability. Always compute 1 − Φ(z) for 'greater than' probabilities.

Your progress

Tick each step as you finish it. Your exact reading position is saved automatically, so Continue drops you back on the same line.

0 of 5 steps complete

Your place saves automatically as you read.

My dashboard