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Advanced algebra and functions
Lesson 2 of 75
Easy practice

Factor and remainder theorems

Objective. Use evaluation to locate factors and unknown coefficients.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

The factor and remainder theorems link evaluating a polynomial at a number to its division properties. The remainder theorem states that dividing f(x) by (x−a) leaves remainder f(a); the factor theorem states that (x−a) is a factor exactly when f(a)=0. Example: for f(x)=x³−6x²+11x−6, since f(1)=1−6+11−6=0, (x−1) is a factor. This lets you test candidate roots quickly using the rational root list from the constant term's factors before dividing fully.

Worked example

Given f(x)=x³+2x²−5x−6, use the factor theorem to show (x+3) is a factor.

Given f(x)=x³+2x²−5x−6
Illustrated card showing Given f(x)=x³+2x²−5x−6
  1. 1Identify that (x+3)=(x−(−3)), so substitute x=−3 into f(x)
  2. 2Compute f(−3)=(−3)³+2(−3)²−5(−3)−6
  3. 3Evaluate: −27+18+15−6=0
  4. 4Since f(−3)=0, the factor theorem confirms (x+3) is a factor

Answer: f(−3)=0, so (x+3) is a factor

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Common mistake. A common error is testing f(−a) instead of f(a) for the factor (x−a); for (x+3)=(x−(−3)), you must substitute x=−3, not x=3, into f(x).

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