Probability laws
Objective. Use complements, unions and intersections consistently.
- 1. Learn
- 2. Worked example
- 3. Practice
- 4. Feedback
- 5. Continue
Learn: the key idea
Probability laws give consistent rules for combining event probabilities, where the complement rule states P(A') = 1 − P(A), the addition rule for any two events states P(A∪B) = P(A) + P(B) − P(A∩B), and for mutually exclusive events P(A∩B) = 0 so the formula simplifies to P(A∪B) = P(A) + P(B). The subtraction of P(A∩B) in the general addition rule avoids double-counting outcomes that satisfy both events. For example, if P(A) = 0.4, P(B) = 0.5 and P(A∩B) = 0.2, then P(A∪B) = 0.4 + 0.5 − 0.2 = 0.7. These laws underpin almost all further probability calculations including conditional probability and independence.
Worked example
Given P(A) = 0.3, P(B) = 0.6 and P(A∩B) = 0.15, use the probability laws to find P(A∪B).
- 1Recall the addition law: P(A∪B) = P(A) + P(B) − P(A∩B).
- 2Substitute the values: P(A∪B) = 0.3 + 0.6 − 0.15.
- 3Add the first two: 0.3 + 0.6 = 0.9.
- 4Subtract the intersection: 0.9 − 0.15 = 0.75.
Answer: 0.75
Concept mastery
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Practice
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Start practisingCommon mistake. Students frequently add P(A) + P(B) without subtracting P(A∩B) even when the events overlap, double-counting outcomes in both events. Always check whether events are mutually exclusive before omitting the intersection term.
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