Integration modelling
Objective. Interpret accumulated change in mathematical contexts.
- 1. Learn
- 2. Worked example
- 3. Practice
- 4. Feedback
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Learn: the key idea
Integration modelling interprets a definite or indefinite integral as the total accumulated change of a quantity whose rate of change is known, such as recovering distance travelled from a velocity function or total cost from marginal cost. If v(t) gives velocity, then ∫v(t) dt gives displacement, and a definite integral ∫ₐᵇ v(t) dt gives the displacement between times a and b, while the integral of speed gives total distance travelled. For example, if v(t) = 6t − 2 metres per second, the displacement from t = 0 to t = 3 is ∫₀³ (6t − 2) dt = [3t² − 2t]₀³ = 27 − 6 = 21 metres. Correctly identifying what quantity the integral represents in context is essential to interpreting the final numerical answer.
Worked example
A particle has velocity v(t) = 4t − 8 m/s for t ≥ 0. Use integration modelling to find its displacement from t = 0 to t = 5 seconds.
- 1Find the antiderivative: s(t) = 2t² − 8t + c, and since displacement is measured from t = 0 let c = 0.
- 2Evaluate at t = 5: s(5) = 2(25) − 40 = 50 − 40 = 10.
- 3Evaluate at t = 0: s(0) = 0.
- 4Displacement = s(5) − s(0) = 10 − 0 = 10 metres.
Answer: 10 metres
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Start practisingCommon mistake. Students often confuse the integral of velocity (displacement) with total distance, not accounting for direction changes when velocity becomes negative. Each interval where velocity is negative must be treated separately and its magnitude added for true distance.
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