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Exponentials and logarithms
Lesson 30 of 75
Review

Growth and decay models

Objective. Build, solve and evaluate continuous and discrete models.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

Growth and decay models use exponential functions to describe quantities that change by a constant percentage over equal time intervals, such as P = P0×bᵗ where P0 is the initial value and b is the growth or decay factor per unit time. If a value grows by 8% each year, b = 1.08, and if it decays by 8%, b = 0.92. For example a £2000 investment growing at 5% yearly gives P = 2000×1.05ᵗ, so after 3 years P = 2000×1.05³ ≈ £2315.25. Logarithms are used to find the time needed to reach a target value by solving the resulting exponential equation for t.

Worked example

A radioactive sample decays according to the growth and decay model N = 800×0.9ᵗ, where t is in days. Find how many days it takes for the sample to fall to 400.

8000.9400
Bar chart of the values 800, 0.9, 400
  1. 1Set N = 400: 400 = 800×0.9ᵗ.
  2. 2Divide both sides by 800: 0.5 = 0.9ᵗ.
  3. 3Take logs: t = ln(0.5)/ln(0.9).
  4. 4Compute: t = (−0.6931)/(−0.1054) ≈ 6.58 days.

Answer: t ≈ 6.58 days

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Common mistake. Students often use b = 1.8 instead of 1.08 for an 8% increase, forgetting that the growth factor is 1 plus the decimal rate, not the decimal rate itself expressed as a whole number.

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