Reverse compound change
Objective. Recover original values from repeated growth or depreciation.
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- 2. Worked example
- 3. Practice
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Learn: the key idea
Reverse compound change finds an original value before a known percentage growth or decay was applied, by dividing the final amount by the overall multiplier rather than taking a percentage of the final amount. If a quantity decayed by r% to give amount A, the original value is A ÷ (1−r/100); for growth it is A ÷ (1+r/100). This works because the original value, multiplied by the multiplier, equals A, so dividing undoes the multiplication. For example, if a price after a 10% reduction is £63, the original price is 63 ÷ 0.9 = £70, not 63 × 1.1.
Worked example
After a 15% pay rise, Sam's salary is £27600. Find his salary before the rise.
- 1Growth multiplier = 1 + 0.15 = 1.15
- 2Original salary × 1.15 = 27600
- 3Original salary = 27600 ÷ 1.15
- 4Compute 27600 ÷ 1.15 = 24000
Answer: £24000
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Start practisingCommon mistake. A common error is to add or subtract the percentage directly from the final value, calculating £63 + 10% = £69.30 instead of dividing by the decay multiplier 0.9 to get £70; percentage change must be undone by division, not addition.
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