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Vectors and geometric proof
Lesson 49 of 75
Challenge

Collinearity

Objective. Prove points are collinear using scalar multiples.

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  2. 2. Worked example
  3. 3. Practice
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Learn: the key idea

Collinearity means three or more points lie on the same straight line, which can be proved using vectors by showing that two vectors formed from the points are scalar multiples of each other. Find two vectors sharing a common point, such as AB and AC, and if AC = kAB for some number k, the points are collinear because they point in the same or opposite direction along one line. If AB = (2, 4) and AC = (3, 6), then AC = 1.5 AB, confirming A, B and C are collinear.

Worked example

Points A, B and C have position vectors OA = (1, 2), OB = (4, 8) and OC = (7, 14). Show that A, B and C demonstrate collinearity.

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Illustrated card showing 1 … 2
  1. 1Find AB = OB − OA = (4−1, 8−2) = (3, 6)
  2. 2Find AC = OC − OA = (7−1, 14−2) = (6, 12)
  3. 3Compare: AC = (6, 12) = 2 × (3, 6) = 2AB
  4. 4Since AC is a scalar multiple of AB sharing point A, the points are collinear

Answer: A, B and C are collinear since AC = 2AB

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Common mistake. Students sometimes conclude collinearity just because two vectors look similar in size without checking they are genuinely scalar multiples with matching components. Always verify that every component scales by the exact same factor k.

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