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Partial differential equations
Lesson 63 of 75
Standard practice

Heat equation

Objective. Solve and interpret diffusion models.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

The heat equation uₜ = αuₓₓ models how temperature or concentration diffuses over time, smoothing out spatial variations, with α the diffusivity controlling the rate. Solving on a finite rod with fixed-zero ends via separation of variables gives solutions uₙ(x,t) = sin(nπx/L)e^(−α(nπ/L)²t), each mode decaying exponentially faster for higher n, so sharp features smooth out quickest. Example: an initial sine profile sin(πx/L) decays as e^(−α(π/L)²t) while preserving its shape, illustrating that diffusion damps amplitude without changing the spatial pattern of a single mode. General initial data is expanded as a Fourier sine series, each term decaying independently.

Worked example

Solve the heat equation uₜ = 4uₓₓ on 0<x<π with u(0,t)=u(π,t)=0 and initial condition u(x,0) = 3sin(2x). Find u(x,t).

4 … 0
Illustrated card showing 4 … 0
  1. 1Match initial data to a single eigenfunction: sin(2x) corresponds to n=2 on [0,π]
  2. 2Eigenvalue for mode n is λₙ = n², so λ₂ = 4
  3. 3Time decay factor is e^(−αλₙt) = e^(−4·4·t) = e^(−16t)
  4. 4Combine with amplitude 3: u(x,t) = 3sin(2x)e^(−16t)

Answer: u(x,t) = 3sin(2x)e^(−16t)

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Common mistake. Students expect heat-equation solutions to oscillate in time like wave solutions; because the time dependence is e^(−λt), not sinusoidal, modes only decay, never oscillate.

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