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Proof and mathematical language
Lesson 2 of 75
Easy practice

Sets and mappings

Objective. Use set operations, images, inverse images and Cartesian products.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

Sets collect objects, and mappings (functions) assign to each element of a domain exactly one element of a codomain, written f:A→B. The image of a subset S⊆A is f(S)={f(x):x∈S}, while the inverse image of T⊆B is f⁻¹(T)={x∈A:f(x)∈T}, and this works even when f has no inverse function. The Cartesian product A×B={(a,b):a∈A,b∈B} underlies graphs of functions and relations. For f:ℝ→ℝ, f(x)=x², the image of [−1,2] is [0,4], and the inverse image of {4} is {−2,2}. Distinguishing f(S) from f⁻¹(T) and remembering inverse images always exist (as sets) are core skills for later analysis.

Worked example

For the mapping f:ℝ→ℝ given by f(x)=x²−1, find the inverse image f⁻¹({3}).

ℝ→ℝ given by f(x)=x²−1
Illustrated card showing ℝ→ℝ given by f(x)=x²−1
  1. 1We need all x with f(x)=3, i.e. x²−1=3.
  2. 2Rearrange to x²=4.
  3. 3Take square roots: x=2 or x=−2.
  4. 4Check: f(2)=4−1=3 and f(−2)=4−1=3, both valid, so f⁻¹({3})={−2,2}.

Answer: {−2, 2}

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Common mistake. Students assume f⁻¹(T) requires f to be invertible, writing it only when f⁻¹ exists as a function. In fact f⁻¹(T) is simply the set of preimages and is always defined, even for non-injective f.

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