Separable equations
Objective. Solve separable initial-value problems.
- 1. Learn
- 2. Worked example
- 3. Practice
- 4. Feedback
- 5. Continue
Learn: the key idea
A separable equation is a first-order ODE that can be written as dy/dx = f(x)g(y), so all y-terms move to one side and all x-terms to the other before integrating. Rearrange to (1/g(y)) dy = f(x) dx, integrate both sides, then use the initial condition to fix the constant. For example dy/dx = xy gives ∫(1/y) dy = ∫x dx, so ln|y| = x²/2 + C, hence y = Ae^(x²/2). Always check y = 0 is not a lost solution when dividing by g(y), and substitute the initial value last to pin down A exactly.
Worked example
Solve the separable equation dy/dx = 2xy with y(0) = 3, giving y as a function of x.
- 1Separate: (1/y) dy = 2x dx
- 2Integrate: ln|y| = x² + C
- 3Apply y(0)=3: ln3 = C
- 4Exponentiate: y = 3e^(x²)
Answer: y = 3e^(x²)
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Start practisingCommon mistake. Dividing by g(y) without checking g(y) = 0 silently discards the constant solution y = 0; for dy/dx = y², y ≡ 0 solves it but vanishes once you divide by y². Always state it separately.
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