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Probability
Lesson 39 of 75
Challenge

Expectation and variance

Objective. Calculate moments and use linearity of expectation.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

The expectation E(X) of a random variable is its probability-weighted average value, calculated as Σ xp(x) for discrete X, representing the long-run mean over many repeated trials. Variance Var(X) = E(X²) − [E(X)]² measures the spread of X around this mean, with larger variance indicating more variability in outcomes. Linearity of expectation states E(aX + b) = aE(X) + b and crucially E(X + Y) = E(X) + E(Y) even when X and Y are dependent, making it a remarkably powerful computational shortcut. For a fair die, E(X) = 3.5 and E(X²) = 91/6, so Var(X) = 91/6 − 3.5² = 35/12.

Worked example

A random variable X has P(X=1) = 0.3, P(X=2) = 0.5, P(X=3) = 0.2. Find the expectation E(X).

A random variable X has P…
Illustrated card showing A random variable X has P(X=1) = 0
  1. 1Recall E(X) = Σ xp(x), multiplying each value by its probability.
  2. 2Compute each term: 1(0.3) = 0.3, 2(0.5) = 1.0, 3(0.2) = 0.6.
  3. 3Add these weighted values together: 0.3 + 1.0 + 0.6.
  4. 4Simplify the sum to obtain the expectation.

Answer: E(X) = 1.9

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Common mistake. Students assume Var(aX) = aVar(X), forgetting the scaling factor is squared; since variance measures squared deviations, the correct identity is Var(aX) = a²Var(X).

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