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Further vectors and 3D geometry
Lesson 46 of 75
Introduction

Scalar product

Objective. Use dot products for projection and angle.

  1. 1. Learn
  2. 2. Worked example
  3. 3. Practice
  4. 4. Feedback
  5. 5. Continue

Learn: the key idea

The scalar (dot) product of two vectors a and b is defined as a·b = |a||b|cos θ, where θ is the angle between them, and equivalently computed in component form as the sum of the products of corresponding components. This product is used to find the angle between vectors via cos θ = (a·b)/(|a||b|), to test perpendicularity (a·b=0 means the vectors are perpendicular), and to find the scalar projection of one vector onto another as (a·b)/|b|. For example, if a=(1,2,2) and b=(2,−1,2), then a·b = 2−2+4 = 4.

Worked example

Find the angle between the vectors a = (3,0,4) and b = (1,2,2), using the scalar product, to one decimal place in degrees.

3 … 0
Illustrated card showing 3 … 0
  1. 1Compute a·b = (3×1)+(0×2)+(4×2) = 3+0+8 = 11
  2. 2Find magnitudes: |a|=√(9+0+16)=√25=5, |b|=√(1+4+4)=√9=3
  3. 3cos θ = 11/(5×3) = 11/15
  4. 4θ = arccos(11/15) ≈ 42.8°

Answer: θ ≈ 42.8°

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Common mistake. Students compute the dot product by multiplying the magnitudes without the cosine term, or confuse it with the vector (cross) product, producing a vector instead of a scalar. The dot product always gives a single number, never a vector.

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